In a 48 ltr mixture, the ratio of milk and water is 5:3. How much water should be added in the mixture so as the ratio will become 3:5?

• Total quantity of mixture = 48 liters
• Initial ratio of milk : water = 5 : 3
• Let’s find the initial quantity of milk and water:
  • Milk = (5 / (5 + 3)) × 48 = (5 / 8) × 48 = 30 liters
  • Water = 48 - 30 = 18 liters
• Let x liters of water be added
• New quantity of water = 18 + x
• Milk remains unchanged = 30 liters
• New ratio of milk : water = 3 : 5

So we can write the equation as:

30 / (18 + x) = 3 / 5

Cross-multiply:

30 × 5 = 3 × (18 + x)
150 = 54 + 3x
3x = 96
x = 32

Water to be added = 32 liters

Answer: 32 liters