8 litres are drawn from a cask full of wine and is then filled with water. This operation is performed three more times. The ratio of the quantity of wine now left in cask to that of the water is 16 : 65. How much wine the cask hold originally?

Let the quantity of the wine in the cask originally be x litres

  Then, quantity of wine left in cask after 4 operations = $x1-\frac{8}{x}4$litres

$\therefore \frac{x1-\frac{8}{x}4}{x} = \frac{16}{81}$  

  $\Rightarrow 1-\frac{8}{x}4=\frac{2}{3}4$ 

$\Rightarrow x=24$