One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture.

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Accepted Answer

Let the percentage of benzene = X (30 - X)/(X- 25) = 6/4 = 3/2 => 5X = 135 X = 27 So, required percentage of benzene = 27 %

One type of liquid contains 25 % of benzene, the other contains 30% of benzene. A can is filled with 6 parts of the first liquid and 4 parts of the second liquid. Find the percentage of benzene in the new mixture.

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