Suppose the vessel initially contains 8 litres of liquid.
Let x litres of this liquid be replaced with water.
Quantity of water in new mixture = |
❨ |
3 - |
3x |
+ x |
❩ |
litres |
8 |
Quantity of syrup in new mixture = |
❨ |
5 - |
5x |
❩ |
litres |
8 |
∴ |
❨ |
3 - |
3x |
+ x |
❩ |
= |
❨ |
5 - |
5x |
❩ |
8 |
8 |
⟹ 5x + 24 = 40 - 5x
⟹ 10x = 16
So, part of the mixture replaced = |
❨ |
8 |
x |
1 |
❩ |
= |
1 |
. |
5 |
8 |
5 |