If the diagonals of a rhombus are 24cm and 10cm the area and the perimeter of the rhombus are respectively.

Area =  $\frac{1}{2}*diagonal1*\frac{1}{2}diagonal2$ =  $\frac{1}{2}*24*10$ sq.cm  

$\frac{1}{2}*daigonal1=\frac{1}{2}*24=12cm$ 

$\frac{1}{2}*diagonal2=\frac{1}{2}*10=5cm$ 

side of a rhombus = (12)² + (5)² = 169      => AB = 13cm