A large field of 700 hectares is divided into two parts. The difference of the areas of the two parts is one-fifth of the average of the two areas. What is the area of the smaller part in hectares?

Let the areas of the two parts be x and (700-x) hectares

therefore,  $x-700-x=\frac{1}{5}\frac{x+700-x}{2}$

  $\Rightarrow 2x-700=70$

  $\Rightarrow x=385$

So, the two parts are 385 and 315.

 Hence, Area of the smaller = 315 hectares