What is the least number of squares tiles required to pave the floor of a room 15.17 m long and 9.02 m broad?

Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm. 

Area of each tile =  $41\times 41cm2$  

Required number of tiles  =  $\frac{1517\times 902}{41\times 41}$= 814