Out of three numbers, the first is twice the second and is half of the third. If the average of three number is 56, the three number in order are?

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Accepted Answer

Let second number = x So, first number = 2x and third number= 4x ∴ ( x + 2x + 4x ) / 3 = 56 ⇒ 7x = 168 ⇒ x = 24 So the numbers are 48,24, 96,

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