January 7, 1992 was Tuesday. Find the day of the week on the same date after 5 years, i.e., on January 7, 1997?

We can say that ,
During the interval we have two leap years as 1992 and 1996 and it contains February of both these years.
∴ The interval has ( 5 + 2 ) = 7 days = 0 odd day.
Hence, January 7, 1997 was also Tuesday.