Convert the recurring decimal 0.1\u0305\u030536 (with 36 repeating after the initial 1) to a fraction in lowest terms. Identify the exact rational form.
-
A136/1000
-
B136/999
-
C136/990
-
D3/22
-
E13/90
Answer
Correct Answer: 3/22
Explanation
Introduction / Context:Recurring decimals that include a non-repeating part followed by a repeating block can be converted to fractions using a standard algebraic technique. Here, the decimal is 0.1363636… where “36” repeats after an initial non-repeating “1”.
Given Data / Assumptions:
- Let x = 0.1363636… with non-repeating part length m = 1 (the digit “1”) and repeating block length n = 2 (“36”).
Concept / Approach:Use the formula derived from shifting decimals: If x = N.R. + R (repeating), then 10^(m+n) x − 10^m x eliminates the repeating tail. The fraction is then an integer over 9…90…0 with n nines and m zeros.
Step-by-Step Solution:Let x = 0.1363636…100x = 13.636363… (shift by two for “36”).10x = 1.363636… (shift by one for the non-repeating “1”).Subtract: 100x − 10x = 13.636363… − 1.363636… = 12.273 = 12.273?? (better use integer blocks).Cleaner approach: write digits: up to first repeat: 0.1 | 36 36 36… ⇒ numerical block method gives (136 − 1) / (99 × 10) = 135 / 990.Reduce: 135/990 = 27/198 = 3/22.
Verification / Alternative check:3/22 ≈ 0.13636… Exactly matches the repeating pattern with “36”.
Why Other Options Are Wrong:
- 136/999 and 136/990 mis-handle the lengths of the non-repeating and repeating parts.
- 136/1000 corresponds to the terminating decimal 0.136, not repeating.
- 13/90 is a simplified-looking fraction but does not reproduce 0.13636…
Common Pitfalls:Forgetting to include a zero after the n nines to account for the m non-repeating digits or failing to reduce the final fraction completely.
Final Answer:3/22