Find the remainder when f(x) = x 4 - 6x 3 + 2x 2 + 3x + 1 is divided by (x - 2)?

When f(x) = x⁴ - 6x³ + 2x² + 3x + 1 is divided by (x - 2), then remainder can be calculated by putting x - 2 = 0
i.e. x = 2
Now, put x = 2 in f(x)
f(2) = (2)⁴ - 6(2)³ + 2(2)² + 3 x 2 + 1
= 16 - 48 + 8 + 6 + 1 = -17
∴ The remainder will be - 17.