CK169JROS2419TXKM??PV

Putting A=1, B=2, C=3,..., M=13,....,X=24,Y=25, Z=26, we have :

  $JR = \frac{J + R}{2} + 2 = \frac{10 + 18 }{2} + 2 = 16$

$CK = \frac{C + K}{2} + 2 = \frac{ 3 + 11}{2} + 2 = 9$

$TX = \frac{T + X}{2}+ 2 = \frac{20 + 24}{2} + 2 = 24$

$OS = \frac{O + S}{2} + 2 = \frac{15 + 19}{2} + 2 = 19$

 So, the missing numbers are :

21 and 14

Hence, the answer is (b).