Let us draw a figure below as per given question.
Given ∝ = cot-1 (3.2) and β = cosec-1(2.6)
In triangle ΔPAD, AD = h cot ∝
In triangle ΔPBD, BD = h cot β
In triangle Δ ABD,
AB2 = AD2 + BD2
= h2(cot2∝ + cot2 β )
⇒ 1002 = h2{ cot2 ∝ + (cosec2 β - 1) }
⇒ 1002= h2 { (3.2)2 + (2.6)2 - 1} = 16h2
⇒ h = 25 m.
