A number of two digits has 3 for its unit's place,and the sum of digits is 1/7 of the number itself, The number is

Let us assume the ten's place digit be x.
Then, the number = 10x + 3
and sum of digits = x + 3
According to question,
So, ( x + 3 ) = 1/7( 10x + 3 )
⇔7x + 21 =10x +3
⇔ 3x = 18
⇔ x = 6
The number = 10x + 3 = 10 x 6 + 3 = 60 + 3 = 63