The value of k for which kx + 3y - k + 3 = 0 and 12x + ky = k, have infinite solutions, is

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Accepted Answer

For infinite solution a1/a2 = b1/2 = c1/c2 ⇒ K/12 = 3/K = (-K + 3)/ -K ⇒ K/12 = 3/K ⇒ K2 = 36 ∴ K = √36 = 6

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