The value of 1/(log 2 π) + 1/(log 6 π) is?

Given exp. = 1/(log₂ π) + 1/(log₆ π)
= log_π 2 + log_π 6
= log_π (2 x 6)
= log_π12
Since 12 > π so the value of given expression is more than 1.