On both sides of a straight road 1760 m long, trees are planted at equal intervals of 20 m, including trees at the ends on each side. What is the maximum total number of trees that can be planted?

Aptitude Number System Difficulty: Easy
Choose an option
  • A
    174
  • B
    176
  • C
    180
  • D
    178
  • E
    172

Answer

Correct Answer: 178

Explanation

Introduction / Context:Equally spaced placements along a segment are a classic “inclusive endpoints” counting problem. When the spacing is d along a segment of length L, the number of points on one side is (L / d) + 1, provided trees are placed at both ends. Since there are two sides of the road, double the per-side count for the total.

Given Data / Assumptions:

  • Road length L = 1760 m.
  • Spacing d = 20 m between consecutive trees.
  • Trees are planted on both sides and at both ends on each side.

Concept / Approach:For one side, with trees at both endpoints, the count is N_side = (L / d) + 1. Then total trees = 2 * N_side, because the same pattern is repeated on the other side. The key is not to forget the extra “+1” that arises from including both endpoints.

Step-by-Step Solution:

Compute per side: L / d = 1760 / 20 = 88.Include both endpoints: N_side = 88 + 1 = 89.Trees on both sides: Total = 2 * 89 = 178.

Verification / Alternative check:Visualize marks every 20 m from 0 to 1760 on one side: positions 0, 20, …, 1760 (inclusive). Counting by step size confirms 89 positions per side, validating the formula.

Why Other Options Are Wrong:176 ignores one of the endpoints across both sides. 180 assumes an extra interval or double-counts. 174 and 172 are undercounts due to missing endpoints or misapplied spacing.

Common Pitfalls:Using only L / d without adding 1, or forgetting to multiply by 2 for both sides of the road.

Final Answer:178

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