Complete the sequence of odd squares: __, 9, 25, 49, 81, 121.

Introduction / Context:The sequence lists squares of consecutive odd numbers. Identifying this property lets us find the term preceding 9 (which is 3^2).

Given Data / Assumptions:

• Known terms: 9, 25, 49, 81, 121 = 3^2, 5^2, 7^2, 9^2, 11^2.

Concept / Approach:

• Preceding odd number is 1; its square is 1.

Step-by-Step Solution:

Verification / Alternative check:Sequence strictly follows (2n−1)^2; with n = 1 gives 1, matching the missing place.

Why Other Options Are Wrong:

• 3,4,5 are not squares of an odd integer preceding 3^2 in this pattern.
• None of these: Not applicable because 1 is valid.

Common Pitfalls:

• Assuming arithmetic progression of the values instead of recognizing squared odds.

Final Answer:1