A man losses 20% of his money. After sending 25 % of the remainder, he has ₹ 480 left. What is the amount of money he originally had?

Let a man have = ₹ N.
Remainder money, after losses 20% of his money
= N - 20% of N
= N - (N x 20)/100
= (5N - N)/5
= 4N/5
Remainder money, after spending 25% of his remainder money
= 4N/5 - 25% of (4N/5)
= 4N/5 - (4N/5) x (25/100)
= 4N/5 - N/5
= (4N - N)/5
= 3N/5
According to the question,
3N/5 = 480
⇒ x = 480 x 5/3 = ₹ 800