In how many different ways can 3 students be associated with 4 chartered accountants,assuming that each chartered accountant can take at most one student?

12

36

24

16

Correct Answer: 24

Explanation:

Number of permutations = $4 P 3$ = 24

Question

In how many different ways can 3 students be associated with 4 chartered accountants,assuming that each chartered accountant can take at most one student?

Accepted Answer

Number of permutations = 4 P 3 = 24

In how many different ways can 3 students be associated with 4 chartered accountants,assuming that each chartered accountant can take at most one student?

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