In how many ways can a group of 5 men and 2 women be made out of a total of 7 men and 3 women?

Question

Accepted Answer

Required number of ways = (7C5 x 3C2) = (7C2 x 3C1) = ❨ 7…

Required number of ways = (⁷C₅ x ³C₂) = (⁷C₂ x ³C₁) =	❨	7 x 6	x 3	❩	= 63.
		2 x 1

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