A cistern can be filled by two pipes A and B in 4 hours and 6 hours respectively. When full, the tank can be emptied by a third pipe C in 8 hours . If all the taps be turned on at the same time, the cistern will be full in?
Correct Answer: 3 hours 26 min.
Explanation:
Net filling in 1 hour = (1/4 + 1/6 - 1/8) = 7/24
∴ Time taken to fill the cistern = (24/7) hrs. = 3 hrs. 26 min.