In the given figure ∠QPR = 90°, QR = 26 cm, PM = 6 cm, MR = 8 cm and ∠PMR = 90°, find the area of ΔPQR.

Given in the question, QR = 26 cm, PM = 6 cm, MR = 8 cm
According to question, in Δ PMR
(Pythagoras Theorem)
PR = √PM² + MR² = √36 + 64 = √ 100 = 10 cm
According to question, in Δ PQR
(Pythagoras Theorem)
PQ = √QR² - PR² = √26² - 10² = √576 - 100 = √ 476 = 24
∴ area of triangle ∆PQR = Base length x Height / 2
⇒ area of triangle ∆PQR = PR x PQ / 2
⇒ area of triangle ∆PQR = 10 x 24 / 2 = 10 x 12
⇒ area of triangle ∆PQR = 120