In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

Question

Accepted Answer

Total number of balls = (8 + 7 + 6) = 21. Let E = event that the ball drawn is neither red nor green = event that the ball d…

∴ P(E) =	n(E)	=	7	=	1	.
	n(S)		21		3

Let E	= event that the ball drawn is neither red nor green
	= event that the ball drawn is blue.

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