If one rolls a fair sides die twice, what is the probability that the die will land on the same number on both the occasions?
Correct Answer: 1/6
Explanation:
Let E = Event of getting same number on both the occasions
= (1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)
∴ n(E) = 6
∴ Required probability = 6/62 = 1/6
