The number of tosses that have to be made in order that there is 99% probability of getting at least one head is?

Corresponding to n tosses, the Probability of getting no head = (1/2)ⁿ and,
Therefore, the probability of getting at least one head = 1 - (1/2)ⁿ
Now, 1 - (1/2)ⁿ ≥ 99/100
⇒ (1/2)ⁿ ≤ 1/100
⇒ n ≥ 7