A box has 8 red, 7 blue, and 6 green balls. One ball is drawn at random. What is the probability that it is neither red nor green?
Aptitude
Probability
Difficulty: Easy
Choose an option
-
A1/3
-
B2/3
-
C7/22
-
D1/7
-
E9 21
Answer
Correct Answer: 1/3
Explanation
Given data
- Red = 8, Blue = 7, Green = 6; Total = 21.
Concept/ApproachNeither red nor green means blue.
Step-by-Step calculation P(blue) = 7 ÷ 21 = 1 ÷ 3
Verification/AlternativeComplement: 1 − P(red or green) = 1 − (8+6)÷21 = 1 − 14÷21 = 7÷21.
Final Answer1/3