What is the probability of getting a total of 9 from two throws of a die?

Given data

• Two throws (equivalently, two dice) ⇒ 36 ordered outcomes.
• Target sum = 9.

Concept/ApproachList the ordered pairs that sum to 9.

Step-by-step calculationFavourable pairs: (3,6), (4,5), (5,4), (6,3) ⇒ 4 outcomesProbability = 4/36 = 1/9

Verification/AlternativeCounts for sums follow the standard 1,2,3,4,5,6,5,4,3,2,1 pattern; sum 9 has 4 ways.

Common pitfallsMissing order (e.g., counting (4,5) and (5,4) as one).

Final Answer1/9