In a simultaneous throw of two dice, what is the probability of getting a doublet ?

In a simultaneous throw of two dice, n(S) = 6 x 6 = 36

Let E = event of getting a doublet = { (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}

  $P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{6}{36}=\frac{1}{6}$