There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?

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Accepted Answer

Total cases of checking in the hotels = 4 x 4 x 4 = 64 ways. Cases when 3 men are checking in different hotels = 4×3×2 = 24 ways. Required probability =24/64 = 3/8

There are four hotels in a town. If 3 men check into the hotels in a day then what is the probability that each checks into a different hotel?

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