Three unbiased coins are tossed. What is the probability of getting at most 2 heads?

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Accepted Answer

∵ n(S) = (2)3 = 8 E = Event of getting 0, or 1 or 2 heads = {TTT, TTH, THT, HTT, HHT, HTH, THH} ⇒ n(E) = 7 ∴ P(E) = n(E)/n(S) = 7/8

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