What is the probability of getting a sum 9 from two throws of a dice ?

Question

Accepted Answer

In two throws of a die, n(s)=(6 x 6)=36 let E= Event of geting a sum 9={(3,6),(4,5),(5,4),(6,3)} P(E) = n(E)/n(S) = 4/36 = 1/9

Discussion & Comments