When two dice are thrown, the probability that the difference of the number on the dice is 2 or 3 is?

The favourable cases are (1, 3), (2, 4) , (3, 5), (4, 6) and (1, 4), (2, 5), (3, 6) and their reversed cases like (3, 1), (4, 2), (5, 3)...
Total number of favourable cases = 2 x 7
∴ Required Probability P(E) = 14/36 = 7/18