The least multiple of 7, which leaves a remainder of 4, when divided by 6, 9, 15 and 18 is:

Let required number be 90k + 4, which is multiple of 7.

Least value of k for which (90k + 4) is divisible by 7 is k = 4.

∴ Required number = (90 x 4) + 4   = 364.