A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?

Question

Accepted Answer

Let the length of the train be x metres and its speed by y m/sec. Then, x = 8 ⟹ x = 8y …

Now,	x + 264	= y
	20

∴ Speed = 22 m/sec =	❨	22 x	18	❩	km/hr = 79.2 km/hr.
			5

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