2 kmph = |
❨ |
2 x |
5 |
❩ |
m/sec = |
5 |
m/sec. |
18 |
9 |
4 kmph = |
❨ |
4 x |
5 |
❩ |
m/sec = |
10 |
m/sec. |
18 |
9 |
Let the length of the train be x metres and its speed by y m/sec.
Then, |
❨ |
x |
❩ |
= 9 and |
❨ |
x |
❩ |
= 10. |
|
|
∴ 9y - 5 = x and 10(9y - 10) = 9x
⟹ 9y - x = 5 and 90y - 9x = 100.
On solving, we get: x = 50.
∴ Length of the train is 50 m.