Let the length of the first train be
x metres.
Then, the length of the second train is |
❨ |
x |
❩ |
metres. |
2 |
Relative speed = (48 + 42) kmph = |
❨ |
90 x |
5 |
❩ |
m/sec = 25 m/sec. |
18 |
∴ |
[x + (x/2)] |
= 12 or |
3x |
= 300 or x = 200. |
25 |
2 |
∴ Length of first train = 200 m.
Let the length of platform be y metres.
Speed of the first train = |
❨ |
48 x |
5 |
❩ |
m/sec = |
40 |
m/sec. |
18 |
3 |
⟹ 600 + 3y = 1800
⟹ y = 400 m.