Let x be the greater real root of x^2 − 16 = 0 and y be the greater real root of y^2 − 9y + 20 = 0. Compare x and y.
Aptitude
Quadratic Equation
Difficulty: Easy
Choose an option
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Aif x > y
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Bif x ≥ y
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Cif x < y
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Dif x ≤ y
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Eif x = y
Answer
Correct Answer: if x < y
Explanation
Introduction / Context: Two quadratics with easily factorable forms allow immediate determination of greater roots. We then compare those values directly.
Given Data / Assumptions:
- x^2 − 16 = 0 ⇒ roots ±4, greater x = 4.
- y^2 − 9y + 20 = 0 ⇒ (y − 4)(y − 5) = 0 ⇒ roots 4 and 5, greater y = 5.
Concept / Approach: Factorization and identification of the larger root for each equation.
Step-by-Step Solution:
x = 4 (greater root of first).y = 5 (greater root of second).Therefore x < y.Verification / Alternative check: Numeric comparison is straightforward; no alternative method needed.
Why Other Options Are Wrong: They contradict the ordering 4 < 5.
Common Pitfalls: Accidentally picking the smaller root 4 for y instead of 5; the prompt specifies the greater root.
Final Answer: if x < y