The quadrictic equation whose roots are 3 and -1, is

Given that, the roots of the quadrictic equation are 3 and -1.
Let α = 3 and β = -1
Sum of roots = α + β = 3 - 1 = 2
Products of roots = α . β = (3) (-1) = -3
∴ Required quadric equation is
x² - (α + β)x + α β = 0
⇒ x² - (2)x + (-3) = 0
⇒ x² - 2x - 3 = 0