₹ 600 are divided among A, B and C such that ₹ 40 more then 2/5th of A's share, ₹ 20 more then 2/7 th of B's Share and ₹ 10 more then 9/17 th of C's share, all are equal. What is B's share?

2A/5 + 40 = 2B/7 + 20 = 9C/17 + 10 = K
Then, A = (5/2) x (K - 40), B = (7/2) x (K - 20), C = (17/9) x (K - 10)
According to the question, A + B + C = 600
⇒ (5/2) x ( K - 40) + (7/2) x (K - 20) + (17/9) x (K - 10) = 600
⇒ 45 x (K - 40 ) + 63 x (K - 20) + 34 x (K - 10) = 10800
⇒ 45K - 1800 + 63K - 1260 + 34K - 340 = 10800
⇒ 142K - 3400 = 10800
⇒ 142K = 10800 + 3400
⇒ 142K = 14200
∴ K = 14200/142 =100
∴ B = (7/2) x (K - 20) = (7/2) x (100 - 20)
= (7 x 80)/2 = 7 x 40
= ₹ 280