Quantity I= Let the three numbers will be 5x, 6x and 10x respectively
ATQ
10x+5x−6x=126
9x=126 X=14
So largest number =10x=10×14=140
Quantity II=let x and y are two numbers
ATQ
12% of x=25%of y And their difference is 78
So first no.=150 2nd no.=72
Hence Quantity I < Quantity II