The number of oranges in three baskets are in the ratio of 3 : 4 : 5. In which ratio the no. of oranges in first two baskets must be increased so that the new ratio becomes 5 : 4 : 3?

Let,   B1 : B2 : B3 = 3x : 4x : 5x 

again  B1 : B2 : B3 = 5y : 4y : 3y

Since there is increase in no.of oranges in first two baskets only, it means the no. of oranges remains constant in the third basket

Therefore,   5x = 3y

Hence    3x : 4x : 5x   =>    $\frac{9y}{5}:\frac{12y}{5}:\frac{15y}{5}$ = 9y:12y:15y

and       5y : 4y : 3y   =>   25x : 20x : 15x

Therfore, increment in first basket = 16

Increment in second basket = 8

Thus, required ratio = 16/8 = 2:1