In a class, 50 students play cricket, 20 students play football and 10 play both cricket and football. How many play at least one of these two games?
Correct Answer: 60
Explanation:
Given: n(C) = 50, n(F) = 20, n(C ∪ F) = 10.
Number of students playing at least one of these two games = n (C ∪ F) = n (C) + n (F) – n (C ∩ F)
= 50 + 20 – 10 = 60.