If S and T are two sets such that S has 21 elements, T has 32 elements, and S ∩ T has 11 elements, how many elements does S ∪ T have?

Question

Accepted Answer

Given in the question, n(S) = 21, n(T) = 32, n(S ∩ T) = 11, n(S ∪ T) = ? Using the formula, n(S ∪ T) = n(S) + n(T) – n(S ∩ T) = 21 + 32 – 11 = 42 Hence, S ∪ T has 42 elements.

If S and T are two sets such that S has 21 elements, T has 32 elements, and S ∩ T has 11 elements, how many elements does S ∪ T have?

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