Find the value of a 3 + b 3 + c 3 - 3abc when a = 225, b = 226 , c = 227

We know that,
a³ + b³ + c³ - 3abc
= (a + b + c) 1/2 [(a - b) ² + (b - c) ² + (c - a) ²]
= (225 + 226 + 227) 1/2 [1 + 1 + 4]
= 678 x 3 = 2034