From a group of men and women, 15 women leave from it, then there are 2 men for each women. After this, 45 men leave , then there are 5 women for each men. Find the double of the number of women in the beginning.?

Let at present, there are c men, then number of women = 5c
Before the men had left
number of men = c + 45 and
number of women = 5c
∴ c + 45 = 2 x 5c
⇒ 9c = 45
∴ c = 45/9 = 5
Hence, number of women in the beginning
= 5c + 15 = 5 x 5 + 15
= 25 + 15 = 40
∴ Double of the women = 40 x 2 = 80