(0.75)31-0.75+0.75+0.752+1 = ?

$\frac{(0.75)3}{1-0.75}+0.75+(0.75)2+1=\frac{(0.75)3+(1-0.75)\left(1\right)2+(0.75)2+1\times 0.75}{1-0.75}$ 

=  $\frac{(0.75)3+\left(1\right)3-(0.75)3}{1-0.75} =\frac{1}{0.25}=4=2$