If x = √3 + 1 and y = √3 - 1 , then the value of (x2 + y2) is: √3 - 1 √3 + 1

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Accepted Answer

x = (√3 + 1) x (√3 + 1) = (√3 + 1)2 = …

x =	(√3 + 1)	x	(√3 + 1)	=	(√3 + 1)²	=	3 + 1 + 2√3	= 2 + √3.
	(√3 - 1)		(√3 + 1)		(3 - 1)		2

y =	(√3 - 1)	x	(√3 - 1)	=	(√3 - 1)²	=	3 + 1 - 2√3	= 2 - √3.
	(√3 + 1)		(√3 - 1)		(3 - 1)		2

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