Find x such that both occurrences of x in the equation x = (√162 × √128) / x are equal.
Aptitude
Square Root and Cube Root
Difficulty: Easy
Choose an option
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A10
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B12
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C14
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D16
Answer
Correct Answer: 12
Explanation
Problem restatementDetermine the common value of x that satisfies x = (√162 × √128) / x.
Given data
- Equation: x = (√162 × √128) / x
Concept/ApproachUse √a × √b = √(ab). Multiply both sides by x to obtain a quadratic in x.
Step-by-step calculationx = √162 × √128 / x = √(162 × 128) / xx2 = √(20736) = 144x = √144 = 12 (taking the positive principal value)
Verification/AlternativeCheck: √162 × √128 = √20736 = 144; then (144) / 12 = 12, which equals x.
Common pitfallsForgetting to combine radicals or missing that x appears in denominator; also note that in typical aptitude contexts, the positive root is expected.
Final Answer12