A jeep travels a certain distance taking 6 hrs in forward journey, during the return journey increased speed 12km/hr takes the times 4 hrs. What is the distance travelled by the jeep is ?

Given a jeep travels a certain distance taking 6 hrs in forward journey
During the return journey, it takes 4 hrs with an increased speed 12 km/hr
Let 'x' be the distance.
Now, speed is given by distance/time.
Here the difference between both speeds = 12

  $\frac{x}{4} - \frac{x}{6} = 12$

  $\frac{3x - 2x}{12} = 12$

=> x = 144 km

Therefore, the distance travelled by the jeep in forward or return journey is x = 144 km.